circle

Question: If the circle ${{x}^{2}}+{{y}^{2}}+6x-2y+k=0$ bisects the circumference of the circle ${{x}^{2}}+{{y}^{2}}+2x-6y-15=0,$ then $k=$



1) 21
2) – 21
3) 23
4) – 23
Solution: Explanation: No Explanation
System of circles

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