circle

Question: If the two circles $2{{x}^{2}}+2{{y}^{2}}-3x+6y+k=0$ and ${{x}^{2}}+{{y}^{2}}-4x+10y+16=0$ cut orthogonally, then the value of k is



1) 41
2) 14
3) 4
4) 0
Solution: Explanation: No Explanation
System of circles

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