circle

Question: The equation of a circle that intersects the circle ${{x}^{2}}+{{y}^{2}}+14x+6y+2=0$ orthogonally and whose centre is (0, 2) is



1) ${{x}^{2}}+{{y}^{2}}-4y-6=0$
2) ${{x}^{2}}+{{y}^{2}}+4y-14=0$
3) ${{x}^{2}}+{{y}^{2}}+4y+14=0$
4) ${{x}^{2}}+{{y}^{2}}-4y-14=0$
Solution: Explanation: No Explanation
System of circles

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