circle

Question: The equation of the circle having the lines ${{x}^{2}}+2xy+3x+6y=0$ as its normals and having size just sufficient to contain the circle $x(x-4)+y(y-3)=0$ is



1) ${{x}^{2}}+{{y}^{2}}+3x-6y-40=0$
2) ${{x}^{2}}+{{y}^{2}}+6x-3y-45=0$
3) ${{x}^{2}}+{{y}^{2}}+8x+4y-20=0$
4) ${{x}^{2}}+{{y}^{2}}+4x+8y+20=0$
Solution: Explanation: No Explanation
System of circles

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