circle

Question: One of the limit point of the coaxial system of circles containing ${{x}^{2}}+{{y}^{2}}-6x-6y+4=0$ , ${{x}^{2}}+{{y}^{2}}-2x$ $-4y+3=0$ is



1) $(-1,\,1)$
2) $(-1,\,2)$
3) $(-2,\,1)$
4) $(-2,\,2)$
Solution: Explanation: No Explanation
System of circles

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