circle

Question: If a circle passes through the point (1, 2) and cuts the circle ${{x}^{2}}+{{y}^{2}}=4$ orthogonally, then the equation of the locus of its centre is

1) ${{x}^{2}}+{{y}^{2}}-3x-8y+1=0$

2) ${{x}^{2}}+{{y}^{2}}-2x-6y-7=0$

3) $2x+4y-9=0$

4) $2x+4y-1=0$

Solution:

Explanation: No Explanation

System of circles

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)