circle

Question: The polar of the point (5, –1/2) w.r.t circle ${{(x-2)}^{2}}+{{y}^{2}}=4$ is



1) $5x-10y+2=0$
2) $6x-y-20=0$
3) $10x-y-10=0$
4) $x-10y-2=0$
Solution: Explanation: No Explanation
Chord of contact of tangent Pole and Polar

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