circle

Question: $y=mx$ is a chord of a circle of radius a and the diameter of the circle lies along x-axis and one end of this chord in origin .The equation of the circle described on this chord as diameter is



1) $(1+{{m}^{2}})({{x}^{2}}+{{y}^{2}})-2ax=0$
2) $(1+{{m}^{2}})({{x}^{2}}+{{y}^{2}})-2a(x+my)=0$
3) $(1+{{m}^{2}})({{x}^{2}}+{{y}^{2}})+2a(x+my)=0$
4) $(1+{{m}^{2}})({{x}^{2}}+{{y}^{2}})-2a(x-my)=0$
Solution: Explanation: No Explanation
Chord of contact of tangent Pole and Polar

Rate this question:

Average rating: (0 votes)

Previous Question Next Question