circle

Question: The points of intersection of the line $4x-3y-10=0$ and the circle ${{x}^{2}}+{{y}^{2}}-2x+4y-20=0$ are



1) $(-2,-6),(4,2)$
2) $(2,\,6),(-4,-2)$
3) $(-2,\,6),(-4,\,2)$
4) None of these
Solution: Explanation: No Explanation
Tangent and normal to a circle

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