circle

Question: A tangent to the circle ${{x}^{2}}+{{y}^{2}}=5$ at the point $(1,–2)$..... the circle ${{x}^{2}}+{{y}^{2}}-8x+6y+20=0$



1) Touches
2) Cuts at real points
3) Cuts at imaginary points
4) None of these
Solution: Explanation: No Explanation
Tangent and normal to a circle

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