circle

Question: The equations of the tangents to the circle ${{x}^{2}}+{{y}^{2}}-6x+4y=12$ which are parallel to the straight line $4x+3y+5=0$ , are



1) $3x-4y-19=0,\,\,3x-4y+31=0$
2) $4x+3y-19=0,\,\,4x+3y+31=0$
3) $4x+3y+19=0,\,\,4x+3y-31=0$
4) $3x-4y+19=0,3x-4y+31=0$
Solution: Explanation: No Explanation
Tangent and normal to a circle

Rate this question:

Average rating: (0 votes)

Previous Question Next Question