Categories > circle > Equations of circle > A line is drawn through a fixed point $P(\alpha ,\ \beta )$ to cut the circle ${{x}^{2}}+{{y}^{2}}={{r}^{2}}$ at A and B. Then $PA\ .\ PB$ is equal to

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Question: A line is drawn through a fixed point $P(\alpha ,\ \beta )$ to cut the circle ${{x}^{2}}+{{y}^{2}}={{r}^{2}}$ at A and B. Then $PA\ .\ PB$ is equal to


1) ${{(\alpha +\beta )}^{2}}-{{r}^{2}}$
2) ${{(\alpha +\beta )}^{2}}-{{r}^{2}}$
3) ${{(\alpha -\beta )}^{2}}+{{r}^{2}}$
4) None of these
Solution: Explanation: No Explanation
Equations of circle Geometrical problems regarding circle

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