circle

Question: The locus of the centre of a circle which touches externally the circle ${{x}^{2}}+{{y}^{2}}-6x-6y+14=0$ and also touches the y-axis, is given by the equation



1) ${{x}^{2}}-6x-10y+14=0$
2) ${{x}^{2}}-10x-6y+14=0$
3) ${{y}^{2}}-6x-10y+14=0$
4) ${{y}^{2}}-10x-6y+14=0$
Solution: Explanation: No Explanation
Equations of circle Geometrical problems regarding circle

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