circle

Question: If one end of a diameter of the circle ${{x}^{2}}+{{y}^{2}}-4x-6y+11=0$ be (3, 4), then the other end is



1) (0, 0)
2) (1, 1)
3) (1, 2)
4) (2, 1)
Solution: Explanation: No Explanation
Equations of circle Geometrical problems regarding circle

Rate this question:

Average rating: (0 votes)

Previous Question Next Question