A point moves such that the sum of its distances from two fixed points (ae,0) and (–ae,0) is always 2a. Then equation of its locus is

Question

Accepted Answer

$\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{a}^{2}}(1-{{e}^{2}})}=1$

Answer

$\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{a}^{2}}(1-{{e}^{2}})}=1$

Answer

$\frac{{{x}^{2}}}{{{a}^{2}}(1-{{e}^{2}})}+\frac{{{y}^{2}}}{{{a}^{2}}}=1$

Answer

None of these

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