coordinate

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• If the points $(x+1,\,2),\ (1,x+2),\ \left( \frac{1}{x+1},\frac{2}{x+1} \right)$are collinear, then x is

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• If $\begin{vmatrix} {{x_1}}&{{y_1}}&1\\ {{x_2}}&{{y_2}}&1\\ {{x_3}}&{{y_3}}&1 \end{vmatrix} = \begin{vmatrix} {{a_1}}&{{b_1}}&1\\ {{a_2}}&{{b_2}}&1\\ {{a_3}}&{{b_3}}&1 \end{vmatrix}$, then the two triangle with vertices $({{x}_{1}},{{y}_{1}}),\,({{x}_{2}},{{y}_{2}}),\,$ $({{x}_{3}},{{y}_{3}})$ and $({{a}_{1}},{{b}_{1}}),\,$$\,({{a}_{2}},{{b}_{2}}),$ $({{a}_{3}},{{b}_{3}})$ must be

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