If the vertices of a triangle be $(am_{1}^{2},2a{{m}_{1}}),\,(am_{2}^{2},2a{{m}_{2}})$ and $(am_{3}^{2},2a{{m}_{3}}),$ then the area of the triangle is

Question

Accepted Answer

${{a}^{2}}({{m}_{2}}-{{m}_{3}})({{m}_{3}}-{{m}_{1}})({{m}_{1}}-{{m}_{2}})$

Answer

$a({{m}_{2}}-{{m}_{3}})({{m}_{3}}-{{m}_{1}})({{m}_{1}}-{{m}_{2}})$

Answer

$({{m}_{2}}-{{m}_{3}})({{m}_{3}}-{{m}_{1}})({{m}_{1}}-{{m}_{2}})$

Answer

None of these

coordinate

Question: If the vertices of a triangle be $(am_{1}^{2},2a{{m}_{1}}),\,(am_{2}^{2},2a{{m}_{2}})$ and $(am_{3}^{2},2a{{m}_{3}}),$ then the area of the triangle is

coordinate

Question: If the vertices of a triangle be $(am_{1}^{2},2a{{m}_{1}}),\,(am_{2}^{2},2a{{m}_{2}})$ and $(am_{3}^{2},2a{{m}_{3}}),$ then the area of the triangle is

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