Categories > pair-st-lines > Bisectors of the angle between the lines > If the bisectors of the angles between the pairs of lines given by the equation $a{{x}^{2}}+2hxy+b{{y}^{2}}=0$ and $a{{x}^{2}}+2hxy+b{{y}^{2}}+\lambda ({{x}^{2}}+{{y}^{2}})=0$ be coincident, then $\lambda =$

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Question: If the bisectors of the angles between the pairs of lines given by the equation $a{{x}^{2}}+2hxy+b{{y}^{2}}=0$ and $a{{x}^{2}}+2hxy+b{{y}^{2}}+\lambda ({{x}^{2}}+{{y}^{2}})=0$ be coincident, then $\lambda =$


1) a
2) b
3) $h$
4) Any real number
Solution: Explanation: No Explanation
Bisectors of the angle between the lines Point of intersection of the lines

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