pair-st-lines

Question: The angle between the lines represented by the equation $a{{x}^{2}}+2hxy+b{{y}^{2}}=0$is given by

1) $\tan \theta =\frac{2({{h}^{2}}-ab)}{(a+b)}$

2) $\tan \theta =\frac{2\sqrt{{{h}^{2}}-ab}}{(a+b)}$

3) $\tan \theta =\frac{2({{h}^{2}}-ab)}{\sqrt{a+b}}$

4) $\tan \theta =\frac{2\sqrt{{{h}^{2}}+ab}}{(a+b)}$

Solution:

Explanation: No Explanation

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