atomic-structure

Question: The energy of an electron revolving in ${n^{th}}$ Bohr's orbit of an atom is given by the expression



1) ${E_n} = - \frac{{2{\pi ^2}{m^4}{e^2}{z^2}}}{{{n^2}{h^2}}}$
2) ${E_n} = - \frac{{2{\pi ^2}m{e^2}{z^2}}}{{{n^2}{h^2}}}$
3) ${E_n} = - \frac{{2{\pi ^2}m{e^4}{z^2}}}{{{n^2}{h^2}}}$
4) ${E_n} = - \frac{{2\pi {m^2}{e^2}{z^4}}}{{{n^2}{h^2}}}$
Solution: Explanation: No Explanation
Atomic Models

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