If a variable line drawn through the point of intersection of straight lines $\frac{x}{\alpha }+\frac{y}{\beta }=1$and $\frac{x}{\beta }+\frac{y}{\alpha }=1$ meets the coordinate axes in A and B, then the locus of the mid point of $AB$ is

Question

Accepted Answer

$\alpha \beta (x+y)=2xy(\alpha +\beta )$

Answer

$\alpha \beta (x+y)=xy(\alpha +\beta )$

Answer

$(\alpha +\beta )(x+y)=2\alpha \beta xy$

Answer

None of these

st-line

Question: If a variable line drawn through the point of intersection of straight lines $\frac{x}{\alpha }+\frac{y}{\beta }=1$and $\frac{x}{\beta }+\frac{y}{\alpha }=1$ meets the coordinate axes in A and B, then the locus of the mid point of $AB$ is

st-line

Question: If a variable line drawn through the point of intersection of straight lines $\frac{x}{\alpha }+\frac{y}{\beta }=1$and $\frac{x}{\beta }+\frac{y}{\alpha }=1$ meets the coordinate axes in A and B, then the locus of the mid point of $AB$ is

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