Categories > st-line > Concurrency of three lines > If the lines $ax+y+1=0,x+by+1=0$ and $x+y+c=0$ (a, b, c being distinct and different from 1) are concurrent, then $\frac{1}{1-a}+\frac{1}{1-b}+\frac{1}{1-c}=$

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Question: If the lines $ax+y+1=0,x+by+1=0$ and $x+y+c=0$ (a, b, c being distinct and different from 1) are concurrent, then $\frac{1}{1-a}+\frac{1}{1-b}+\frac{1}{1-c}=$


1) 0
2) 1
3) $\frac{1}{a+b+c}$
4) None of these
Solution: Explanation: No Explanation
Concurrency of three lines

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