Categories > st-line > Distance between two lines > Let $\alpha $ be the distance between the lines $-x+y=2$ and $x-y=2$, and $\beta $ be the distance between the lines $4x-3y=5$ and $6y-8x=1$, then

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Question: Let $\alpha $ be the distance between the lines $-x+y=2$ and $x-y=2$, and $\beta $ be the distance between the lines $4x-3y=5$ and $6y-8x=1$, then


1) $20\sqrt{2}\beta =11\alpha $
2) $20\sqrt{2}\alpha =11\beta $
3) $11\sqrt{2}\beta =20\alpha $
4) None of these
Solution: Explanation: No Explanation
Distance between two lines Perpendicular distance of the line from a point Position of point w.r.t. line

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