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Question: Distance between the parallel lines $3x+4y+7=0$ and $3x+4y-5=0$ is


1) $\frac{2}{5}$
2) $\frac{12}{5}$
3) $\frac{5}{12}$
4) $\frac{3}{5}$
Solution: Explanation: No Explanation
Distance between two lines Perpendicular distance of the line from a point Position of point w.r.t. line

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