Categories > st-line > Distance between two lines > If p and $p'$be the distances of origin from the lines $x\sec \alpha +y \text{cosec }\alpha =k$ and $x\cos \alpha -y\sin \alpha =k\cos 2\alpha $, then $4{{p}^{2}}+{{{p}'}^{2}}$=

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Question: If p and $p'$be the distances of origin from the lines $x\sec \alpha +y \text{cosec }\alpha =k$ and $x\cos \alpha -y\sin \alpha =k\cos 2\alpha $, then $4{{p}^{2}}+{{{p}'}^{2}}$=


1) k
2) $2k$
3) ${{k}^{2}}$
4) $2{{k}^{2}}$
Solution: Explanation: No Explanation
Distance between two lines Perpendicular distance of the line from a point Position of point w.r.t. line

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