st-line

Question: The vertices of a triangle OBC are $(0,\ 0),\ (-3,\ -1)$ and $(-1,\ -3)\ $ respectively. Then the equation of line parallel to BC which is at $\frac{1}{2}$ unit distant from origin and cuts OB and OC, is



1) $2x+2y+\sqrt{2}=0$
2) $2x+2y-\sqrt{2}=0$
3) $2x-2y+\sqrt{2}=0$
4) None of these
Solution: Explanation: No Explanation
Slope of line Equation of line in different forms

Rate this question:

Average rating: (0 votes)

Previous Question Next Question