The equation of the straight line joining the point $(a,\ b)$ to the point of intersection of the lines $\frac{x}{a}+\frac{y}{b}=1$ and $\frac{x}{b}+\frac{y}{a}=1$ is

Question

Accepted Answer

${{a}^{2}}y-{{b}^{2}}x=ab\ (a-b)$

Answer

${{a}^{2}}y+{{b}^{2}}y=ab\ (a+b)$

Answer

${{a}^{2}}y+{{b}^{2}}x=ab$

Answer

${{a}^{2}}x+{{b}^{2}}y=ab\ (a-b)$

st-line

Question: The equation of the straight line joining the point $(a,\ b)$ to the point of intersection of the lines $\frac{x}{a}+\frac{y}{b}=1$ and $\frac{x}{b}+\frac{y}{a}=1$ is

st-line

Question: The equation of the straight line joining the point $(a,\ b)$ to the point of intersection of the lines $\frac{x}{a}+\frac{y}{b}=1$ and $\frac{x}{b}+\frac{y}{a}=1$ is

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