trigonometry

Question: A tower subtends angles $\alpha ,\,2\alpha ,\,3\alpha $respectively at points A, B and $C$, all lying on a horizontal line through the foot of the tower. Then $AB/BC=$



1) $\frac{\sin 3\alpha }{\sin 2\alpha }$
2) $1+2\cos 2\alpha $
3) $2+\cos 3\alpha $
4) $\frac{\sin 2\alpha }{\sin \alpha }$
Solution: Explanation: No Explanation
Height and Distance

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