trigonometry

Question: The angular elevation of a tower CD at a point A due south of it is 60° and at a point B due west of A, the elevation is 30o. If AB = 3 km, the height of the tower is



1) $2\sqrt{3}\,km$
2) $2\sqrt{6}\,km$
3) $\frac{3\sqrt{3}}{2}km$
4) $\frac{3\sqrt{6}}{4}km$
Solution: Explanation: No Explanation
Height and Distance

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