trigonometry

Question: The base of a cliff is circular. From the extremities of a diameter of the base the angles of elevation of the top of the cliff are 30° and 60°. If the height of the cliff be 500 metres, then the diameter of the base of the cliff is



1) $1000\,\sqrt{3}\,m$
2) $2000/\sqrt{3}\,m$
3) $1000/\sqrt{3}\,m$
4) $2000\sqrt{2}\,m$
Solution: Explanation: No Explanation
Height and Distance

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