trigonometry

Question: The angle of elevation of the top of a tower from a point A due south of the tower is $\alpha $and from a point B due east of the tower is $\beta $. If $AB =d$, then the height of the tower is



1) $\frac{d}{\sqrt{{{\tan }^{2}}\alpha -{{\tan }^{2}}\beta }}$
2) $\frac{d}{\sqrt{{{\tan }^{2}}\alpha +{{\tan }^{2}}\beta }}$
3) $\frac{d}{\sqrt{{{\cot }^{2}}\alpha +{{\cot }^{2}}\beta }}$
4) $\frac{d}{\sqrt{{{\cot }^{2}}\alpha -{{\cot }^{2}}\beta }}$
Solution: Explanation: No Explanation
Height and Distance

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