trigonometry

Question: If $x,\,y,\,z$are perpendicular drawn $a,\,b$ and $c$, then the value of $\frac{bx}{c}+\frac{cy}{a}+\frac{az}{b}$will be



1) $\frac{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}{2R}$
2) $\frac{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}{R}$
3) $\frac{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}{4R}$
4) $\frac{2({{a}^{2}}+{{b}^{2}}+{{c}^{2}})}{R}$
Solution: Explanation: No Explanation
Circle connected with triangle

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