trigonometry

Question: If the radius of the circumcircle of an isosceles triangle $PQR$ is equal to $PQ(=PR),$then the angle P is



1) $\frac{\pi }{6}$
2) $\frac{\pi }{3}$
3) $\frac{\pi }{2}$
4) $\frac{2\pi }{3}$
Solution: Explanation: No Explanation
Circle connected with triangle

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