trigonometry

Question: In a $\Delta ABC$ if the sides are $a=3,\,b=5$ and $c=4$ , then $\sin \frac{B}{2}+\cos \frac{B}{2}$ is equal to



1) $\sqrt{2}$
2) $\frac{\sqrt{3}+1}{2}$
3) $\frac{\sqrt{3}-1}{2}$
4) 1
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

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