trigonometry

Question: The area of triangle $ABC,$ in which $a=1,\ b=2$ , $\angle C=60{}^\circ $ is

1) $\frac{1}{2}$

2) $\sqrt{3}$

3) $\frac{\sqrt{3}}{2}$

4) $\frac{3}{2}$

Solution:

Explanation: No Explanation

Relation between sides and angles Solutions of triangles

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