trigonometry

Question: In a triangle $PQR$ , $\angle R=\frac{\pi }{2}.$ If $\tan \left( \frac{P}{2} \right)$ and $\tan \left( \frac{Q}{2} \right)$ are the roots of the equation $a{{x}^{2}}+bx+c=0(a\ne 0).$ then



1) $a+b=c$
2) $b+c=a$
3) $a+c=b$
4) $b=c$
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

Rate this question:

Average rating: (0 votes)

Previous Question Next Question