If ${{p}_{1}},{{p}_{2}},{{p}_{3}}$ are altitudes of a triangle $ABC$ from the vertices $A,B,C$ and $\Delta $ the area of the triangle, then $p_{1}^{-2}+p_{2}^{-2}+p_{3}^{-2}$ is equal to

Question

Accepted Answer

$\frac{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}{4{{\Delta }^{2}}}$

Answer

$\frac{a+b+c}{\Delta }$

Answer

$\frac{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}{{{\Delta }^{2}}}$

Answer

None of these

trigonometry

Question: If ${{p}_{1}},{{p}_{2}},{{p}_{3}}$ are altitudes of a triangle $ABC$ from the vertices $A,B,C$ and $\Delta $ the area of the triangle, then $p_{1}^{-2}+p_{2}^{-2}+p_{3}^{-2}$ is equal to

trigonometry

Question: If ${{p}_{1}},{{p}_{2}},{{p}_{3}}$ are altitudes of a triangle $ABC$ from the vertices $A,B,C$ and $\Delta $ the area of the triangle, then $p_{1}^{-2}+p_{2}^{-2}+p_{3}^{-2}$ is equal to

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