trigonometry

Question: In $\Delta ABC$ if $a=2,b=4$ and $\angle C={{60}^{o}}$ , then $\angle A$ and $\angle B$ are equal to



1) ${{90}^{o}},{{30}^{o}}$
2) ${{60}^{o}},{{60}^{o}}$
3) ${{30}^{o}},{{90}^{o}}$
4) ${{60}^{o}},{{45}^{o}}$
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

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