trigonometry

Question: If $\alpha ,\beta ,\gamma $ are angles of a triangle, then ${{\sin }^{2}}\alpha +{{\sin }^{2}}\beta +{{\sin }^{2}}\gamma -2\cos \alpha \cos \beta \cos \gamma $ is



1) 2
2) –1
3) –2
4) 0
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

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