trigonometry

Question: In a $\Delta ABC,$ if $\frac{b+c}{11}=\frac{c+a}{12}=\frac{a+b}{13}$ , then $\cos C=$



1) $\frac{7}{5}$
2) $\frac{5}{7}$
3) $\frac{17}{36}$
4) $\frac{16}{17}$
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

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