trigonometry

Question: If in a triangle ABC side $a=(\sqrt{3}+1)$ cms and $\angle B={{30}^{o}},$ $\angle C={{45}^{o}}$ , then the area of the triangle is



1) $\frac{\sqrt{3}+1}{3}c{{m}^{2}}$
2) $\frac{\sqrt{3}+1}{2}c{{m}^{2}}$
3) $\frac{\sqrt{3}+1}{2\sqrt{2}}c{{m}^{2}}$
4) $\frac{\sqrt{3}+1}{3\sqrt{2}}c{{m}^{2}}$
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

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