trigonometry

Question: The smallest angle of the triangle whose sides are $6+\sqrt{12},\sqrt{48},\sqrt{24}$ is

1) $\frac{\pi }{3}$

2) $\frac{\pi }{4}$

3) $\frac{\pi }{6}$

4) None of these

Solution:

Explanation: No Explanation

Relation between sides and angles Solutions of triangles

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