trigonometry

Question: ABC is a triangle such that $\sin (2A+B)=$ $\sin (C-A)=$ $-\sin (B+2C)=\frac{1}{2}$. If A, B and C are in A.P., then A, B and C are



1) ${{30}^{o}},{{60}^{o}},{{90}^{o}}$
2) ${{45}^{o}},{{60}^{o}},{{75}^{o}}$
3) ${{45}^{o}},{{45}^{o}},{{90}^{o}}$
4) ${{60}^{o}},{{60}^{o}},{{60}^{o}}$
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

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