trigonometry

Question: In $\Delta \,ABC$ , $\frac{\cos \frac{1}{2}(B-C)}{\sin \frac{1}{2}A}=$



1) $\frac{b-c}{a}$
2) $\frac{b+c}{a}$
3) $\frac{a}{b-c}$
4) $\frac{a}{b+c}$
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

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