trigonometry

Question: In $\Delta ABC,$ if $(a+b+c)(a-b+c)$ =3ac, then



1) $\angle B={{60}^{o}}$
2) $\angle B={{30}^{o}}$
3) $\angle C={{60}^{o}}$
4) $\angle A+\angle C={{90}^{o}}$
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

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