trigonometry

Question: In $\Delta ABC,$ $1-\tan \frac{A}{2}\tan \frac{B}{2}=$



1) $\frac{2c}{a+b+c}$
2) $\frac{a}{a+b+c}$
3) $\frac{2}{a+b+c}$
4) $\frac{4a}{a+b+c}$
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

Rate this question:

Average rating: (0 votes)

Previous Question Next Question