Categories > trigonometry > Relation between sides and angles > In $\Delta ABC,\left( \cot \frac{A}{2}+\cot \frac{B}{2} \right)\,\left( a{{\sin }^{2}}\frac{B}{2}+b{{\sin }^{2}}\frac{A}{2} \right)$ =

trigonometry

Question: In $\Delta ABC,\left( \cot \frac{A}{2}+\cot \frac{B}{2} \right)\,\left( a{{\sin }^{2}}\frac{B}{2}+b{{\sin }^{2}}\frac{A}{2} \right)$ =


1) $\cot C$
2) $c\cot C$
3) $\cot \frac{C}{2}$
4) $c\cot \frac{C}{2}$
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

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