trigonometry

Question: If $(2\cos x-1)(3+2\cos x)=0,\,0\le x\le 2\pi $, then $x=$

1) $\frac{\pi }{3}$

2) $\frac{\pi }{3},\frac{5\pi }{3}$

3) $\frac{\pi }{2},\frac{5\pi }{3},{{\cos }^{-1}}\left( -\frac{3}{2} \right)$

4) $\frac{5\pi }{3}$

Solution:

Explanation: No Explanation

Solution of trigonometric equations

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