trigonometry

Question: The equation ${{\sin }^{4}}x+{{\cos }^{4}}x+\sin 2x+\alpha =0$is solvable for



1) $-\frac{1}{2}\le \alpha \le \frac{1}{2}$
2) $-3\le \alpha \le 1$
3) $-\frac{3}{2}\le \alpha \le \frac{1}{2}$
4) $-1\le \alpha \le 1$
Solution: Explanation: No Explanation
Solution of trigonometric equations

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