trigonometry

Question: If $\frac{\tan 3\theta -1}{\tan 3\theta +1}=\sqrt{3}$, then the general value of $\theta $is

1) $\frac{n\pi }{3}+\frac{\pi }{12}$

2) $\frac{n\pi }{3}+\frac{7\pi }{36}$

3) $n\pi +\frac{7\pi }{12}$

4) $n\pi +\frac{\pi }{12}$

Solution:

Explanation: No Explanation

Solution of trigonometric equations

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